2[3(x-2)-1]+1=(2x+1)3+7

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Solution for 2[3(x-2)-1]+1=(2x+1)3+7 equation:


Simplifying
2[3(x + -2) + -1] + 1 = (2x + 1) * 3 + 7

Reorder the terms:
2[3(-2 + x) + -1] + 1 = (2x + 1) * 3 + 7
2[(-2 * 3 + x * 3) + -1] + 1 = (2x + 1) * 3 + 7
2[(-6 + 3x) + -1] + 1 = (2x + 1) * 3 + 7

Reorder the terms:
2[-6 + -1 + 3x] + 1 = (2x + 1) * 3 + 7

Combine like terms: -6 + -1 = -7
2[-7 + 3x] + 1 = (2x + 1) * 3 + 7
[-7 * 2 + 3x * 2] + 1 = (2x + 1) * 3 + 7
[-14 + 6x] + 1 = (2x + 1) * 3 + 7

Reorder the terms:
-14 + 1 + 6x = (2x + 1) * 3 + 7

Combine like terms: -14 + 1 = -13
-13 + 6x = (2x + 1) * 3 + 7

Reorder the terms:
-13 + 6x = (1 + 2x) * 3 + 7

Reorder the terms for easier multiplication:
-13 + 6x = 3(1 + 2x) + 7
-13 + 6x = (1 * 3 + 2x * 3) + 7
-13 + 6x = (3 + 6x) + 7

Reorder the terms:
-13 + 6x = 3 + 7 + 6x

Combine like terms: 3 + 7 = 10
-13 + 6x = 10 + 6x

Add '-6x' to each side of the equation.
-13 + 6x + -6x = 10 + 6x + -6x

Combine like terms: 6x + -6x = 0
-13 + 0 = 10 + 6x + -6x
-13 = 10 + 6x + -6x

Combine like terms: 6x + -6x = 0
-13 = 10 + 0
-13 = 10

Solving
-13 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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